Dan White wrote:
On 10/20/13 14:27 +0200, Pol Hallen wrote:
Howdy :-)
I need create a script to set programmatically password to sasldb users
#!/bin/bash
pass=test
saslpasswd -c -u domain.org user0
how pass variable $pass to this script?
/bin/echo "$password" | /usr/sbin/saslpasswd2 -a $service_name $username
This is inappropriate for a multi-user system since the password will show
up in a process list.
You can avoid that by *not* using /bin/echo. If you leave it unqualified
you'll get the shell builtin command, and nothing will show up in the process
list.
--
-- Howard Chu
CTO, Symas Corp. http://www.symas.com
Director, Highland Sun http://highlandsun.com/hyc/
Chief Architect, OpenLDAP http://www.openldap.org/project/
