On Wed, May 08, 2013 at 06:22:09PM -0700, James Marshall wrote:
> It shows 6 because a comma-separated literal list, when interpreted as a
> scalar, evaluates to the final value in the list, not the length of the
> list. If you evaluate "scalar(1,2,,4,,7)", it will equal 7. That's the
> comma operator at work-- even though it looks like a list (and both use
> commas), it's really just a sequential set of expressions.
I think I've forgotten more useless perl trivia than I should have...
I use the comma operator sometimes, but never inside scalar(). Didn't
recognize it. TMTOWTMakeAMess.
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