> (Question-1): Does this mean that the DOFs are arranged (at least
> conceptually) as:
>
> U = (u1,v1,u2,v2 ... u4,v4,p1...p4) transposed? (for a 4 noded 2D
> element)

No. It's not arranged like this, but in the end the actual arrangement is 
also not very important. The only thing is that the arrangement is in 
exactly the same order as the global indices that you can get from
  cell->get_dof_indices (...)

W.

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Wolfgang Bangerth                email:            [email protected]
                                 www: http://www.math.tamu.edu/~bangerth/

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