I'll implement it and I'll test the case Q1 Nothing Nothing Q1
for the case Q1 Nothing Nothing Q2 I'm not sure (I've to read the code) what I need for imposing the fluxes on both sides having Q1 on one and Q2 on the other side. I'll see and let you know. >> In the nonsymmetric case, for example: >> >> <Q1-Nothing>--<Nothing-Q2>, > > I think this should work just as in the symmetric case: the returned value > should be no_requirements because each of the pairs > Q1 Nothing > Nothing Q2 > returns no_requirements. > > The only cases that won't work (and for which I have no solution anyway) > are > cases like > <Q1 Q2> -- <Q2 Q1> > > Do you want to see if you could implement such a scheme, starting in the > FiniteElementDomination namespace, FE_Nothing/FE_Q and then FESystem > classes? > > Best > W. > > ------------------------------------------------------------------------- > Wolfgang Bangerth email: [email protected] > www: http://www.math.tamu.edu/~bangerth/ > _______________________________________________ dealii mailing list http://poisson.dealii.org/mailman/listinfo/dealii
