Thank You, Prof. Bangerth. 
I have one more doubt about the output of step-40.
For cycle 0, there are 1024 cells (32*32 mesh). So, we have 33 nodes each, 
along x and y. So, shouldn't the number of DOFs be 1089 instead of 4225?

Regards 
Wasim

On Thursday, April 6, 2023 at 11:27:32 PM UTC+5:30 Wolfgang Bangerth wrote:

> On 4/6/23 10:18, Wasim Niyaz Munshi ce21d400 wrote:
> > How do I get the no.of cells owned by the processor?
>
> Triangulation::n_locally_owned_active_cells().
>
> Best
> W.
>
> -- 
> ------------------------------------------------------------------------
> Wolfgang Bangerth email: bang...@colostate.edu
> www: http://www.math.colostate.edu/~bangerth/
>

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