Your message dated Sat, 12 Nov 2011 04:12:34 -0800 (PST)
with message-id <[email protected]>
and subject line sed -i -e '$w/dev/stdout' -e '$d' testFile
has caused the Debian Bug report #648344,
regarding sed -i '$p;$d' doesn't work
to be marked as done.
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Bug report if necessary, and/or fix the problem forthwith.
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--
648344: http://bugs.debian.org/cgi-bin/bugreport.cgi?bug=648344
Debian Bug Tracking System
Contact [email protected] with problems
--- Begin Message ---
Package: sed
Version: 4.2.1-9
Severity: normal
I expected sed -i '$p;$d' to work. It doesn't.
sed -n '$p;$p' does work.
Tp reproduce:
$ printf "1\n2\n" > testFile
$ sed -n '$p;$p' testFile
2
2
$ sed -i '$p;$d' testFile
$ printf "$?\n"
0
$ cat testFile
1
2
$ sed -i '$d' testFile
$ printf "$?\n"
0
$ cat testFile
1
$
--- End Message ---
--- Begin Message ---
Package: sed
Version: 4.2.1-9
As can be read in the discussion of the bug, http://bugs.debian.org/648344:
sed -i '$p;$d' works as designed. The intention of the bug submitter could
have been run by sed -i -e '$w/dev/stdout' -e '$d' testFile
--- End Message ---
