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On 10/30/2014 11:28 AM, David Wright wrote:
<snip>

Let me make sure I've got this right: you have two different entries
in /etc/fstab that correspond to the same partition, and one of them
says it is fat?  I suppose that explains it then: fsck has to pick one
and goes with the one that says it is fat.

> I've now observed that my box running sid does both: it fscks 
> /dev/sda1 and then emits the same messages as jessie before it's 
> cleared a moment later. (I grabbed a photograph.)
> 
> So the problem now seems to be: why does sid bother with an fstab 
> entry that has "0" at the end, and why does jessie apparently
> throw away the entry that has "1" at the end in favour of the
> second entry?

I can venture some guesses.  Assuming you were still using sysvinit in
sid, checkroot.sh probably unconditionally checks the root without
caring about the order specified in fstab.  fsck also probably just
uses the last entry found when more than one applies rather than
trying to arbitrate using the order entry.

> Would I be correct in guessing that the zero logical sector size
> comes from picking up a number from a FAT-ty location that contains
> zero in a linux partition.

Yep.


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