On Wed, 15 Oct 2014, Stephane Chazelas wrote:
> $ mksh -c 'IFS=; x=abc; printf "<%s>\n" ${x#$*}' x a b | sed -n l
> <\a\300a>$
> <abc>$
Interesting… but all shells diverge on this one.
tglase@tglase:~ $ bash -c 'IFS=; x=abc; printf "<%s>\n" ${x#$*}' x a b | sed -n
l
<abc>$
tglase@tglase:~ $ dash -c 'IFS=; x=abc; printf "<%s>\n" ${x#$*}' x a b | sed -n
l
<a>$
<abc>$
tglase@tglase:~ $ ksh93 -c 'IFS=; x=abc; printf "<%s>\n" ${x#$*}' x a b | sed
-n l
<c>$
tglase@tglase:~ $ mksh -c 'IFS=; x=abc; printf "<%s>\n" ${x#$*}' x a b | sed -n
l
<\a\300a>$
<abc>$
tglase@tglase:~ $ pdksh-5.2.14 -c 'IFS=; x=abc; printf "<%s>\n" ${x#$*}' x a b
| sed -n l
<abc>$
Makes you wonder if ksh93 gets it right, or if bash/pdksh do.
But I agree that mksh’s output is just as broken as dash’s here.
> POSIX requires word splitting be performed upon arithmetic
> expansion. Yes, that's stupid, even more stupid than the way
> $*/$@ are handled in ksh, but that's the way it is.
[…]
> But not mksh (and I'd praise it for doing the right thing here).
>
> $ mksh -c 'IFS=2; echo $((11*11))'
> 121
I’d praise it too, except, your mksh is too old. I was notified
of this POSIX requirement being unearthed, and changed the shell
to comply. (The requirement to parse $((010)) as 8 is worse IMO,
and only done if “set -o posix”.)
tglase@tglase:~ $ mksh -c 'IFS=2; echo $((11*11))'
1 1
tglase@tglase:~ $ mksh -c 'print $KSH_VERSION'
@(#)MIRBSD KSH R50 2014/10/07
Bugfixes to the shell to adhere more strictly to POSIX are frequent.
But this should have been in R50 already.
bye,
//mirabilos
--
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detail in the program, which is as sensible as putting all the prepositions
in English text in bold font. -- Rob Pike in "Notes on Programming in C"
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