Jason Gunthorpe wrote:
>
> What exactly is that checksum a checksum of? I would hope that it is a
> hash of the function signature which should be constant for any kernel
> version. If it is a hash of the contents then there is no point in having
> binary modules..
It is computed from the signature. But it is overzealous in that it follows
to many pointers, i.e. if your signature were
void foo(struct bar p);
and bar is
struct bar {
struct baz *q;
};
then if baz is changed, foo's checksum will also change.
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