>Submitter-Id: net
>Originator: Stefan Karrmann
>Organization:
>Confidential: no
>Synopsis: nearbyint returns always 895
>Severity: serious
>Priority: medium
>Category: c
>Class: wrong-code
>Release: 3.0.3 (Debian testing/unstable)
>Environment:
System: Linux johann 2.4.21 #2 Sun Aug 17 20:52:39 CEST 2003 i686 unknown
Architecture: i686
host: i686-pc-linux-gnu
build: i686-pc-linux-gnu
target: i686-pc-linux-gnu
configured with: ./configure --enable-languages=c++
>Description:
Calling nearbyint returns always 895.0
>How-To-Repeat:
Compile and run:
#include <math.h>
#include <stdio.h>
void show (double x)
{
printf("nearbyint(%+.3e) = %d\n", x, (int)(nearbyint(x)));
if(0.0 == x) return;
x = -x;
printf("nearbyint(%+.3e) = %d\n", x, (int)(nearbyint(x)));
x = 1/x;
printf("nearbyint(%+.3e) = %d\n", x, (int)(nearbyint(x)));
x = -x;
printf("nearbyint(%+.3e) = %d\n", x, (int)(nearbyint(x)));
}
int main ()
{
show(1.1);
show(11);
show(111.1);
}
>Fix:
