Svante Signell, le Tue 11 Feb 2014 18:17:45 +0100, a écrit : > @@ -531,6 +533,7 @@ > argv[i++] = level_buf; > argv[i++] = NULL; > > + /* FIXME: since exevp don't return exec_buf is defined static */
There is no need to make it static: execvp does not return simply because it puts another program in the process. You thus don't even need to care where the data has been allocated: it'll be completely wiped once exec succeeds. Also, I guess you have not really understood what really get static: static char *foo; means that it's the foo pointer whose allocation is made static. Not the data pointed by foo... Apart from that, it seems fine. Samuel -- To UNSUBSCRIBE, email to debian-hurd-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org Archive: http://lists.debian.org/20140211172636.gs10...@type.bordeaux.inria.fr
