Glenn Maynard <[EMAIL PROTECTED]> writes: >> If you make a kernel module that only uses something >> EXPORT_SYMBOL()'d from the kernel, you are NOT in principle >> writing a derivative work. If you use EXPORT_SYMBOL_GPL()'d >> symbols, then you are incurring in (b) above and your kernel >> module is most certainly a derivative work. > > The notion that what is a derivative work changes based on whether a symbol > was declared with EXPORT_SYMBOL or EXPORT_SYMBOL_GPL seems fundamentally > absurd to me. (If somebody is reimplementing the Linux kernel API, he > might just as easily reimplement the "EXPORT_SYMBOL_GPL" symbols, for > compatibility with drivers that need them, for example.)
Someone could even take the Linux kernel, and replace all EXPORT_SYMBOL_GPL with EXPORT_SYMBOL. I see nothing in the GPL prohibiting this. Sure, it wouldn't be nice, but it's legal not to be nice. -- Måns Rullgård [EMAIL PROTECTED] -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]
