Dear Debian users,
I just wanted to make sure that my menu.lst looks good for grub. I wouldn't
want it to fail and not be able to load any operating system. I have two
questions in the comments so please be sure to read them.
I've got four partitions on my primary IDE hard drive
hd0,0 - Windows
hd0,1 - Boot
hd0,2 - Swap
hd0,3 - root
My /boot/grub/menu.lst looks like this:
==============================
default 0
timeout 5
# Windows OS
title Windows 2000
# Can I skip the next two lines if I use this? [ rootnoverify (hd0,0) ]
root (hd0,0)
makeactive
chainloader +1
# Linux OS
title Linux
root (hd0,1)
kernel /vmlinuz root=/dev/hda1 ro
===============================
So that's my initial step to boot windows and debian. When this file was
generated, this is the last thing on the file
==============================
title Debian GNU/Linux, kernel 2.4.18-bf2.4
# Shouldn't this be hd0,1 ?
root (hd0,0)
kernel /vmlinuz root=/dev/hda1 ro
===============================
Why is the second line(root) designated to hd0,0? Shouldn't it be hd0,1
since /boot resides in that partition?
Finally, what safety cautions can I take if this fails?
As always, any help or suggestion is greatly appreciated.
bp
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- Re: grub configuration Bruce Park
- Re: grub configuration Shawn Lamson