Hello all...
Thanks in advance for looking at this - please reply to
[EMAIL PROTECTED]
I have a log file that I need to extract some data from...
the lines I am looking for; are the lines that contain the output from
the command:
date "+ %a %b %d" | sed 's/ //'
or
"Fri Jun 12"
I am using sed to strip away a leading blank space that I am getting
from the date "+ %a %b %d" .
So i have this log see... and I would like to do something like a
grep echo \"`date "+ %a %b %d" | sed 's/ //'`\" arch.log
grabbing only the entries from the log file that have the current date
in front of them.
BUT what I get is:
grep: can't open "Fri
grep: can't open Jun
grep: can't open 12"
can someone please advise me on where I went wrong.
below is a sample of the log file I am working against. (arch.log)
Sun Jun 7 01:30:01 Beginning XTMS Archive
Sun Jun 7 01:51:08 Archived 683 tickets
Mon Jun 8 01:30:02 Beginning XTMS Archive
Mon Jun 8 01:51:17 Archived 712 tickets
Tue Jun 9 01:30:01 Beginning XTMS Archive
Tue Jun 9 01:51:43 Archived 719 tickets
Wed Jun 10 01:30:02 Beginning XTMS Archive
Wed Jun 10 01:45:40 Archived 544 tickets
Thu Jun 11 01:30:02 Beginning XTMS Archive
Thu Jun 11 01:33:01 Archived 110 tickets
Fri Jun 12 01:30:02 Beginning XTMS Archive
Fri Jun 12 01:32:09 Archived 86 tickets
Thanks again - [EMAIL PROTECTED]
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