I think that [EMAIL PROTECTED] is right. WD says my HD is 3249MB, and the kernel says its only 3098MB. But WD also have a remark that it sees 1MB = 1000000B. Now if the kernel treats 1MB as 2^20 = 1048576 then my HD is 3098 * 1048576 = 3248488448 which are, roughly, 3249MB.
Trying it for your HD gives 6140 * 1048576 = 6438256640 > I don't think this is the case since this the drive is a Western Digital > 26400 Caviar and it does report 6GB excatly it reports 6.14...GB > > > ---------- > > From: Lewis, James M. [SMTP:[EMAIL PROTECTED] > > Sent: Tuesday, February 16, 1999 10:56 AM > > To: 'debian-user@lists.debian.org'; 'Person, Roderick' > > Cc: 'The recipient's address is unknown.' > > Subject: RE: Which Kernal supports over 6.0 GB HD > > > > Just a guess. I think it sees the whole thing. Disk drive makers > > sometimes use 1000bytes as 1k, whereas, most folks use 1024. The disk > > folks think 1,000,000,000 bytes is 1G. Others think 1,073,741,824 bytes > > is 1G. 6 x 1G = 6,442,459,944 bytes. Which 6.4G if you use the 1000 > > for 1k base. It depends on which def of 1k you use. I suspect the > > linux utilities use 1024=1k. Read the fine print to see what the drive > > manufacturer uses for 1k. > > > > jim > > > > >---------- > > >From: Person, Roderick[SMTP:[EMAIL PROTECTED] > > >Sent: Tuesday, February 16, 1999 10:28 AM > > >To: 'debian-user@lists.debian.org' > > >Cc: The recipient's address is unknown. > > >Subject: Which Kernal supports over 6.0 GB HD > > > > > >I just bought a 6.4GB but Linux only reads it as 6.0GB, which Kernal do I > > >need to get the full access > > > > > >Thanks. > > > > > > > > >-- > > >Unsubscribe? mail -s unsubscribe [EMAIL PROTECTED] < > > >/dev/null > > > > > > > > > > > -- > Unsubscribe? mail -s unsubscribe [EMAIL PROTECTED] < /dev/null > >
