On Thu, Aug 30, 2001 at 10:51:12PM -0700, Karsten M. Self wrote:
> on Thu, Aug 30, 2001 at 11:09:07PM -0500, ktb ([EMAIL PROTECTED]) wrote:
> > On Thu, Aug 30, 2001 at 08:45:29PM -0700, Vineet Kumar wrote:
> > >
> > > * Brian Schramm ([EMAIL PROTECTED]) [010830 19:41]:
> > > > Is there a way that I can take a passwd file and compare the full name
> > > > data
> > > > in it to the email ldap server and give a a list of what it finds and
> > > > what it
> > > > misses? I am doing this manually but with the number of users that
> > > > there are
> > > > involved it is going to be really time consuming.
> > >
> > > I don't really know what I'm talking about, but this should probably
> > > help you get started:
> > >
> > > awk -F : '{print $5}' /etc/passwd | sed -e "s/^\([^,]*\).*$/\1/"
> > >
> > > That will give you a list of just the full names. Pipe that into
> > > something else that will look each one up in the directory service.
> > >
> > > Not a complete answer, but it's a start...
> >
> > BTW what does [ sed -e "s/^\([^,]*\).*$/\1/" ] accomplish? I'm just
> > grooving on one liners lately and am curious. It seems like -
> > awk -F : '{print $5}' /etc/passwd is all you need to spit out the full
> > names.
>
> Not quite the same thing:
>
> $ awk -F : '/karsten/ {print $5}' /etc/passwd
> Karsten M. Self,,,
>
>
> $ awk -F : '{print $5}' /etc/passwd | sed -e "s/^\([^,]*\).*$/\1/"
> Karsten M. Self
>
> In the original pattern:
>
> sed -e "s/^\([^,]*\).*$/\1/"
>
> We have:
>
> -e: expression to evaluate.
> s: create a substitution using the following pattern.
> / start of expression
> ^ beginning of line (actually, beginning of fifth field
> \( start a substitution
> [^,]* match zero or more instances of any character other than ','
> \) end substitution
> .*$ match to end of line
> / end of expression
> \1 replace with contents of first substitution (the \([^,]*\)
> pattern)
> / end expression
>
> sed is for people who think Perl's too easy to understand.
Thanks for the nice explanation:) What was confusing me is the two
/etc/passwd files I ran the various commands against, non of them had
and ','s' in them. I just tried my progeny box here at work and see
fully what the sed expression is used for.
kent
