On Tue, Apr 25, 2006 at 06:56:27PM +0200, Dennis Stosberg wrote: > [EMAIL PROTECTED] wrote: > > > I'd like to define a symbol ARCH in my Makefile to be the output > > of > > uname -m > > > > The obvious thing, just starting with > > > > ARCH = `uname -m` > > > > didn't seem to work. It defined ARCH to be `uname -m' instead of > > i686 or x86_64. Not unreasonable, but What *is* the way to do > > this? > > With GNU make you can use "ARCH = $(shell uname -m)". > > Regards, > Dennis
Thanks. That worked. Why do I need it? Because I have just one home directory, NFS-mounted and shared between two machines with different architectures. I find it convenient for everything except compiling. -- hendrik -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]