On Wed, May 16, 2007 at 08:46:37PM +0000, Tyler Smith wrote:
> Hi,
>
> I've got a question about a short bash script I wrote. I need it to
> loop over a number of names, and pass a command to grass that includes
> two variations of those names. That was easy. Harder was getting
> getting a letter included in each iteration, starting with A for the
> first one and going up by one each iteration. What I came up with,
> with extra bits snipped, is:
>
> #!/bin/bash
>
> lab_num=41
>
> for map_name in aest_90 bush_90 carol_90 comp_90 \
> hirs_90 roan_90 swan_90 vir_90 ;
>
> do
>
> lab_let=$(echo -n $(printf "\\x$(echo $lab_num)"))
>
> echo "
> $lab_let
> $map_name
> ${map_name}.ps" ;
>
> echo $((lab_num++)) > /dev/null ;
>
> done
>
> The multi-line echo is passing instructions to a GRASS command, and in
> the full script it works fine. This example runs fine without grass as
> a demonstration. What I'm wondering about is the line:
>
> lab_let=$(echo -n $(printf "\\x$(echo $lab_num)"))
>
> This was the only way I could figure out to loop from A to H. But
> since it works on hex escape codes, it won't work past 9. Is there a
> cleaner, more general way to do this?
I think there is:
#!/bin/bash
( cat <<!
A aest_90
B bush_90
C carol_90
D comp_90
E hirs_90
F roan_90
G swan_90
H vir_90
!
) | while read letter name
do
printf '%s\n%s\n%s.ps\n\n' "$letter" "$name" "$name"
done
Hope this helps
--
Karl E. Jorgensen
[EMAIL PROTECTED] http://www.jorgensen.org.uk/
[EMAIL PROTECTED] http://karl.jorgensen.com
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