Eduardo M KALINOWSKI wrote: >> >> Manually diffing the files 50 times is cumbersome. Something like >> >> diff dir1/file*.txt dir2/file*.txt >> >> is what I am after. I do not want to do >> >> diff -r dir1 dir2 >> >> since that compares the other 950 files as well besides the 50 files that >> I want. Any idea how to achieve this in the most generic fashion? Has >> anyone done this kind of thing before? >> >> thanks >> raju >> > for i in `seq 1 50`; do diff dir1/file$i.txt dir2/file$i.txt > > diff$i.txt ; done >
Ok, this works on the command line. But I am looking for something along the lines of bash_script_name dir1/pattern1 dir2/pattern2 where dir1/pattern1, dir2/pattern2 are given as arguments to the script. I could not figure out how to do this inside a bash script. Any idea? raju -- Kamaraju S Kusumanchi http://www.people.cornell.edu/pages/kk288/ http://malayamaarutham.blogspot.com/ -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]