Hello, Can you help me with a bash command? I a directory, I want to extract with a command line for jpg name files. I have a lot of:
icon_3620_0_1.jpg icon_3616_0_1.jpg icon_3563_0_1.jpg I want to extract the number betwen icon_*_0_1.jpg AND I want to use the entire filename too in the same command. The goal is to create a directory called 3620 and move the icon_3620_0_1.jpg file into this directory. So, I did like this for test: # for a in `ls | sed -e s'/_/ /g' | awk '{print $2}'`; do echo icon_$a_0_1.jpg; done I hope it should give me: icon_3620_0_1.jpg icon_3616_0_1.jpg icon_3563_0_1.jpg like the original BUT in my surprise, it shows: icon_.jpg icon_.jpg icon_.jpg icon_.jpg Why? Where is the $a_0_1 gone? Surely I missed something but I cannot find it. Can you tell me how to reproduce the exact filename so? Best regards, -- Tôba -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]