Matej Kosik grabbed a keyboard and wrote: > Hello, > > This morning I have been puzzled by bash. > After typing the following command: > > for i in `seq 1 5`;do echo $i; test $i = 3 && break; done > > I see: > > 1 > 2 > 3 > > Which is OK. > > However, if the "break" command appears in a subshell: > > for i in `seq 1 5`;do echo $i; test $i = 3 && (break); done > > then the "break" command does not seem to have any effect > > 1 > 2 > 3 > 4 > 5 > > I am curious, is this something to be expected?
What do you mean by "appears in a subshell?"
--Dave
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