On 03/11/14 13:56, Alexis wrote: > > Iain M Conochie writes: > >> However: >> >> $: which umask >> $: >> >> So umask is _not_ a program (in the sense that there is no binary >> called umask on the system) > > zsh, however, is more helpful: > > $ which umask > umask: shell built-in command
BASH as current shell (and login) scott@work ~ $ type umask umask is a shell builtin > > > Alexis. > > Kind regards -- "Turns out you can't back a winner in the Gish Gallop" ~ disappointed punter -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of "unsubscribe". Trouble? Contact listmas...@lists.debian.org Archive: https://lists.debian.org/54596a90.3080...@gmail.com
