davidson wrote: > > > > I actually looked with `hd` and expected to see 0x20 there, but > > somehow see none of it: > > > > $ echo $COMP_WORDBREAKS | hd > > 00000000 22 27 40 3e 3c 3d 3b 7c 26 28 3a 0a |"'@><=;|&(:.| > > 0000000c > > Above I count 12 characters piped from echo to hd. The final character > is a newline added by echo, so that leaves 11 characters attributable > to the content of COMP_WORDBREAKS. > > But try this, below. It will tell you the length (in characters) of > the content of COMP_WORDBREAKS. > > $ echo ${#COMP_WORDBREAKS} > 14 > > So, when you do... > > $ echo $COMP_WORDBREAKS | hd > 00000000 22 27 40 3e 3c 3d 3b 7c 26 28 3a 0a |"'@><=;|&(:.| > 0000000c > > ...what accounts for the three missing characters (namely SPACE, TAB, > and NEWLINE)? > > TLDR: The shell's "word splitting" removes them, because you have not > double-quoted the variable.
Oh, I see. Thanks. -- Victor Sudakov VAS4-RIPE http://vas.tomsk.ru/ 2:5005/49@fidonet
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