Why do you need to do this? And why does speed matter? At Tue, 7 Jul 2026 14:18:25 -0400 Eben King <[email protected]> wrote:
> > I have a need to find the upgradable package with the most dependencies. > So far I've got this, in /bin/sh: > > allpkgs="$(apt list --upgradable 2> /dev/null | grep / | cut -f 1 -d / )" > max=0 > countlist="" > for package in $allpkgs ; do > dependencies=$(apt-get --simulate upgrade "$package" | grep upgraded, > | cut -f 1 -d ' ') # get #dependencies, maybe; this is the slow bit > [ "$dependencies" -gt "$max" ] && max="$dependencies" > countlist="$countlist $dependencies $pkgname" > done > > It works, but is definitely not fast. Is there a faster way? > > > -- Robert Heller -- Cell: 413-658-7953 GV: 978-633-5364 Deepwoods Software -- Custom Software Services http://www.deepsoft.com/ -- Linux Administration Services [email protected] -- Webhosting Services
