On Tue, 2020-06-30 at 07:58 -0500, David Richmond wrote: > Thanks, Richard, for all your help. It seems the key press is > recorded correctly by the gprint() debug. For instance, with b, e, > and f: > > Scorearea key press event: keyval 98 (b), string |b|, length 1, > state 0, keycode 11, group 0, is_modifier flag 0
ok, this is what Denemo receives on my Debian installation, so whatever is going on should be fixable, though it is likely to involve some Gtk murk - Gtk supplies names for key presses, IIRC, in two ways depending on whether they should be translated to the user's language or not. Let's concentrate on the simplest case - pressing "b" on your keyboard: To be clear, when you try to set the (unshifted, no caps locked, no alt, no ctrl) key "b" as a shortcut you find that Denemo describes it as keypress "2"? As a first step it would be good to uncomment the lines src/core/kbd-custom.c: 415, 444, 445, 482 in the file src/core/kbd-custom.c these are print statements that will step through the munging, I think, and tell us what Gtk is calling the keypress. Richard > Scorearea key press event: keyval 101 (e), string |e|, length 1, > state 0, keycode 14, group 0, is_modifier flag 0 > Scorearea key press event: keyval 102 (f), string |f|, length 1, > state 0, keycode 3, group 0, is_modifier flag 0 > > Shift + 2 reads as shift + @ (the character above the 2 on my > keyboard): > > Scorearea key press event: keyval 65505 (Shift_L) > Scorearea key press event: keyval 64 (at), string |@|, length 1, > state 1, keycode 19, group 0, is_modifier flag 0 > > The 2 key reads correctly as 2: > > Scorearea key press event: keyval 50 (2), string |2|, length 1, > state 0, keycode 19, group 0, is_modifier flag 0 > > Option + 3 reads as option + £, which I believe is a Mac remapping > (as I thought I could fix via the command center): > > Scorearea key press event: keyval 65513 (Alt_L), string ||, > length 0, state 0, keycode 58, group 1, is_modifier flag 1 > Scorearea key press event: keyval 163 (sterling), string |£|, > length 2, state 8, keycode 20, group 1, is_modifier flag 0 > > The keycode numbers may be a bit weird, but it seems like you use > event->keyval in process_key_event(), so if the print call is > printing the same correctly.... > > I will see if someone has a standard USB keyboard lying around.
