They are unique but you should not make assumptions about the sequence. On Wed, Mar 9, 2016 at 9:01 PM, Sandeep Deshmukh <[email protected]> wrote:
> By default, are the IDs returned by getId() method sequential like 0..(N-1) > where there are N instances of the operator or these IDs are some unique > numbers? > > Regards, > Sandeep > > On Thu, Mar 10, 2016 at 4:41 AM, Thomas Weise <[email protected]> > wrote: > > > You can also assign a custom ID or other any other per-partition > properties > > in the partitioner. > > > > On Wed, Mar 9, 2016 at 3:09 PM, Ashwin Chandra Putta < > > [email protected]> wrote: > > > > > Use the getId() method in OperatorContext. > > > > > > > > > > > > https://www.datatorrent.com/docs/apidocs/com/datatorrent/api/Context.OperatorContext.html#getId() > > > > > > Regards, > > > Ashwin. > > > > > > On Wed, Mar 9, 2016 at 3:05 PM, Ganelin, Ilya < > > [email protected] > > > > > > > wrote: > > > > > > > Given that any single logical operator may have multiple physical > > > > partitions, is there any way for an operator to know something akin > to > > a > > > > partition ID? E.g. part0, part1, etc. > > > > ________________________________________________________ > > > > > > > > The information contained in this e-mail is confidential and/or > > > > proprietary to Capital One and/or its affiliates and may only be used > > > > solely in performance of work or services for Capital One. The > > > information > > > > transmitted herewith is intended only for use by the individual or > > entity > > > > to which it is addressed. If the reader of this message is not the > > > intended > > > > recipient, you are hereby notified that any review, retransmission, > > > > dissemination, distribution, copying or other use of, or taking of > any > > > > action in reliance upon this information is strictly prohibited. If > you > > > > have received this communication in error, please contact the sender > > and > > > > delete the material from your computer. > > > > > > > > > > > > > > > > -- > > > > > > Regards, > > > Ashwin. > > > > > >
