Select count(distinct f0) from t Is supported now, can you please past your error stack trace, is it the parse error or plan promotion error ?
Best, Danny Chan 在 2019年4月2日 +0800 AM11:31，kakasi2...@163.com <kakasi2...@163.com>，写道： > hello， > > The problem is about use ［count（distinct（ID））］，distinct aggregation > notsupported. Does the community have a plan to solve the problem，or have a > temporary solution ? > > > thank you
