>
> Basically I know the function return a list so I want to access each
> element of it. Ideally I can get a List<Expression> ret =
> Expressions.call(FindMethod("myFunc"))
>
Can you elaborate on what do you want? i.e., *List<Expression> ret*
If you want to get the element of a method call result, you can evaluate
the expression and cast it to list.
For example, assume "myFunc" in SqlFunctions.
* public static List<Long> myFunc() { return Arrays.asList(1L, 2L); }*
* MethodCallExpression mce = Expressions.call(SqlFunctions.class,
"myFunc"); List<Long> ret = (List<Long>) Expressions.evaluate(mce);*
Best,
Rui Wang <amaliu...@apache.org> 于2019年12月31日周二 下午12:14写道：
> Hi community,
>
> Let's say I define a function like this:
>
> List<Long> myFunc() {
> // function body
> // do something
> // return a list of long
> }
>
> Then by linq4j library, I can
>
> Expression ret = Expressions.call(
> FindMethod("myFunc")
> )
>
>
> my question is, how to make the returned expression of the call to be a
> list, or something equivalent?
>
> Basically I know the function return a list so I want to access each
> element of it. Ideally I can get a List<Expression> ret =
> Expressions.call(FindMethod("myFunc"))
>
>
> -Rui
>
