My issue is not about parsing. I already have the relational model, I parsed a query to which I want to add add a condition to a RelNode. Now I want to add a RexNode to the LogicalFilter node that renders to: NEW."somecolumn"
How would I construct a RexNode that renders to that when converting the RelNode to SQL. Do I have to extend the SqlDialect to support that? Danny Chan <yuzhao....@gmail.com> schrieb am Di., 18. Feb. 2020, 15:12: > If you want to make NEW a normal sql identifier, you should override it in > the parser to make it unreserved. > > Christian Beikov <christian.bei...@gmail.com>于2020年2月18日 周二下午3:11写道： > > > Hey Danny, > > > > it's not a view, it's a variable in PL/SQL with a row type. The thing > > is, variable names must not be quoted, but I have no idea how to avoid > > quoting for this single use case with the relational algebra model in > > Calcite. > > > > Regards, > > > > Christian > > > > Am 18.02.2020 um 04:22 schrieb Danny Chan: > > > From the case you gave, the “variable” seems a view ? Sorry I’m not > > familiar with the traditional RDBMS. > > > > > > Best, > > > Danny Chan > > > 在 2020年2月17日 +0800 PM1:27，Christian Beikov <christian.bei...@gmail.com > > >，写道： > > >> Hello, > > >> > > >> I asked this before but I guess the question got too big, so I thought > > >> splitting it up might be better. > > >> > > >> I am trying to generate a query from a relational model on which I > did a > > >> few tranformations but I don't know how to refer to a "variable". > > >> > > >> In a SQL trigger, there usually are two variable "OLD" and "NEW" > which I > > >> want to be able to refer to. I tried introducing a "transient scan", > but > > >> unfortunately that won't work because this is not a relation and can't > > >> be quoted. I will workaround this for now by introducing a temporary > > >> relation in the trigger so that I can refer to it, but ideally I want > to > > >> refer to the variable directly. > > >> > > >> The simplest example SQL that I want to be able to produce would look > > >> like this: > > >> > > >> select NEW."some_column" > > >> > > >> The tricky part here is that NEW is not quoted. I don't know how I can > > >> represent this in a relation expression. > > >> > > >> Thanks in advance for any help! > > >> > > >> Regards, > > >> > > >> Christian > > >> > > >
