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https://issues.apache.org/jira/browse/CAMEL-4325?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
]
Cedric de Launois updated CAMEL-4325:
-------------------------------------
Description:
When a REST service returns an HTTP error code (e.g. 404), the URI property of
the exception is incorrect.
The URI is the URI of the origin endpoint of the route.
It should be instead the URI of the endpoint that threw the exception.
For instance, in the following route :
{code:xml}
<route id="restproxy">
<from uri="restlet:http://localhost:9080/oe/ws/offre/{id}"/>
<doTry>
<to uri="restlet:http://bla.dot.com:8080/oe/ws/offre/{id}"/>
<doCatch>
<exception>org.apache.camel.CamelException</exception>
<log message="URI=${exception.uri}"/>
</doCatch>
</doTry>
</route>
{code}
The logged URI is "restlet:http://localhost:9080/oe/ws/offre/{id}"; but should
be instead the real URI used, e.g.
"restlet:http://bla.dot.com:8080/oe/ws/offre/1";.
This bug might be fixed by the following code change in class
org.apache.camel.component.restlet.RestletProducer, method
populateRestletProducerException() :
- String uri = exchange.getFromEndpoint().getEndpointUri();
+ String uri = response.getRequest().getResourceRef()
was:
When a REST service returns an HTTP error code (e.g. 404), the URI property of
the exception is incorrect.
The URI is the URI of the origin endpoint of the route.
It should be instead the URI of the endpoint that threw the exception.
For instance, in the following route :
{code:xml}
<route id="restproxy">
<from uri="restlet:http://localhost:9080/oe/ws/offre/{id}"/>
<doTry>
<to uri="restlet:http://bla.dot.com:8080/oe/ws/offre/{id}"/>
<doCatch>
<exception>org.apache.camel.CamelException</exception>
<log message="URI=${exception.uri}"/>
</doCatch>
</doTry>
</route>
{code}
The logged URI is "restlet:http://localhost:9080/oe/ws/offre/{id}"; but should
be instead the real URI used, e.g.
"restlet:http://bla.dot.com:8080/oe/ws/offre/1";.
This bug might be fixed by the following code change in class
org.apache.camel.component.restlet.RestletProducer, method
populateRestletProducerException() :
- String uri = exchange.getFromEndpoint().getEndpointUri();
+ String uri = response.getRequest().getResourceRef()
> Wrong exception uri when an HTTP error code is returned
> -------------------------------------------------------
>
> Key: CAMEL-4325
> URL: https://issues.apache.org/jira/browse/CAMEL-4325
> Project: Camel
> Issue Type: Bug
> Components: camel-restlet
> Affects Versions: 2.6.0, 2.7.0, 2.8.0
> Reporter: Cedric de Launois
>
> When a REST service returns an HTTP error code (e.g. 404), the URI property
> of the exception is incorrect.
> The URI is the URI of the origin endpoint of the route.
> It should be instead the URI of the endpoint that threw the exception.
> For instance, in the following route :
> {code:xml}
> <route id="restproxy">
> <from uri="restlet:http://localhost:9080/oe/ws/offre/{id}"/>
> <doTry>
> <to uri="restlet:http://bla.dot.com:8080/oe/ws/offre/{id}"/>
> <doCatch>
> <exception>org.apache.camel.CamelException</exception>
> <log message="URI=${exception.uri}"/>
> </doCatch>
> </doTry>
> </route>
> {code}
> The logged URI is "restlet:http://localhost:9080/oe/ws/offre/{id}"; but should
> be instead the real URI used, e.g.
> "restlet:http://bla.dot.com:8080/oe/ws/offre/1";.
> This bug might be fixed by the following code change in class
> org.apache.camel.component.restlet.RestletProducer, method
> populateRestletProducerException() :
> - String uri = exchange.getFromEndpoint().getEndpointUri();
> + String uri = response.getRequest().getResourceRef()
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