Congratulations to Alex~

Lijie Wang <wangdachui9...@gmail.com> 于2024年1月3日周三 14:05写道:

> Congratulations Alex !
>
> Best,
> Lijie
>
> Romit Mahanta <romit.maha...@gmail.com> 于2024年1月3日周三 13:41写道:
>
> > Happy New Year & congratulations Alex!
> >
> > Best,
> >
> > R
> >
> > On Tue, 2 Jan, 2024, 5:45 pm Maximilian Michels, <m...@apache.org> wrote:
> >
> > > Happy New Year everyone,
> > >
> > > I'd like to start the year off by announcing Alexander Fedulov as a
> > > new Flink committer.
> > >
> > > Alex has been active in the Flink community since 2019. He has
> > > contributed more than 100 commits to Flink, its Kubernetes operator,
> > > and various connectors [1][2].
> > >
> > > Especially noteworthy are his contributions on deprecating and
> > > migrating the old Source API functions and test harnesses, the
> > > enhancement to flame graphs, the dynamic rescale time computation in
> > > Flink Autoscaling, as well as all the small enhancements Alex has
> > > contributed which make a huge difference.
> > >
> > > Beyond code contributions, Alex has been an active community member
> > > with his activity on the mailing lists [3][4], as well as various
> > > talks and blog posts about Apache Flink [5][6].
> > >
> > > Congratulations Alex! The Flink community is proud to have you.
> > >
> > > Best,
> > > The Flink PMC
> > >
> > > [1]
> > >
> https://github.com/search?type=commits&q=author%3Aafedulov+org%3Aapache
> > > [2]
> > >
> >
> https://issues.apache.org/jira/browse/FLINK-28229?jql=status%20in%20(Resolved%2C%20Closed)%20AND%20assignee%20in%20(afedulov)%20ORDER%20BY%20resolved%20DESC%2C%20created%20DESC
> > > [3]
> https://lists.apache.org/list?dev@flink.apache.org:lte=100M:Fedulov
> > > [4]
> https://lists.apache.org/list?u...@flink.apache.org:lte=100M:Fedulov
> > > [5]
> > >
> >
> https://flink.apache.org/2020/01/15/advanced-flink-application-patterns-vol.1-case-study-of-a-fraud-detection-system/
> > > [6]
> > >
> >
> https://www.ververica.com/blog/presenting-our-streaming-concepts-introduction-to-flink-video-series
> > >
> >
>


-- 
Best,
renxiang

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