Try, select a.* from tmp_source_fs_price1 a join ( select fund_id,nav_date,CURRENCY,nav,count(1) from tmp_source_fs_price1 group by fund_id,nav_date,CURRENCY,nav having count(1) > 1) b on a.fund_id = b.fund_id ;
The grammar you've mentioned is not supported in hive-0.11.0 (hive-0.13.0, by HIVE-6393) Thanks, Navis 2014-07-24 19:20 GMT+09:00 Adi Reddy <tolla.adire...@gmail.com>: > Hi Team, > > > I am looking for to get duplicate records with in the table (using hive > version : 0.11.0 ) . > > > > Below is my query : select a.* from tmp_source_fs_price1 a, ( select > fund_id,nav_date,CURRENCY,nav,count(1) from tmp_source_fs_price1 group by > fund_id,nav_date,CURRENCY,nav having count(1) > 1) b where a.fund_id = > b.fund_id ; > > > > Exception : NoViableAltException(10@[175:43: (alias= identifier )?]) > > at org.antlr.runtime.DFA.noViableAlt(DFA.java:158) > > at org.antlr.runtime.DFA.predict(DFA.java:144) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser_FromClauseParser.tableSource(HiveParser_FromClauseParser.java:3616) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser_FromClauseParser.fromSource(HiveParser_FromClauseParser.java:2815) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser_FromClauseParser.joinSource(HiveParser_FromClauseParser.java:1316) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser_FromClauseParser.fromClause(HiveParser_FromClauseParser.java:1189) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser.fromClause(HiveParser.java:30719) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser.selectStatement(HiveParser.java:28858) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser.regular_body(HiveParser.java:28766) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser.queryStatement(HiveParser.java:28306) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpression(HiveParser.java:28100) > > at > > org.apache.hadoop.hive.ql.parse.HiveParser.execStatement(HiveParser.java:1213) > > at > org.apache.hadoop.hive.ql.parse.HiveParser.statement(HiveParser.java:928) > > at > org.apache.hadoop.hive.ql.parse.ParseDriver.parse(ParseDriver.java:190) > > at org.apache.hadoop.hive.ql.Driver.compile(Driver.java:418) > > at org.apache.hadoop.hive.ql.Driver.compile(Driver.java:337) > > at org.apache.hadoop.hive.ql.Driver.run(Driver.java:902) > > at > org.apache.hadoop.hive.cli.CliDriver.processLocalCmd(CliDriver.java:259) > > at > org.apache.hadoop.hive.cli.CliDriver.processCmd(CliDriver.java:216) > > at > org.apache.hadoop.hive.cli.CliDriver.processLine(CliDriver.java:413) > > at org.apache.hadoop.hive.cli.CliDriver.run(CliDriver.java:756) > > at org.apache.hadoop.hive.cli.CliDriver.main(CliDriver.java:614) > > at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) > > at > > sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) > > at > > sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) > > at java.lang.reflect.Method.invoke(Method.java:601) > > at org.apache.hadoop.util.RunJar.main(RunJar.java:212) > > FAILED: ParseException line 1:39 cannot recognize input near 'a' ',' '(' in > table source > > > > > > Could you please anyone help me on this. > > > Thanks, > > AdiReddy >