On Tue, Sep 09, 2008 at 10:10:42PM +0200, Ruediger Pluem wrote:
>
>
> On 09/03/2008 01:01 AM, [EMAIL PROTECTED] wrote:
>> Added: httpd/httpd/trunk/modules/filters/sed1.c
>> URL:
>> http://svn.apache.org/viewvc/httpd/httpd/trunk/modules/filters/sed1.c?rev=691418&view=auto
>> ==============================================================================
>> --- httpd/httpd/trunk/modules/filters/sed1.c (added)
>> +++ httpd/httpd/trunk/modules/filters/sed1.c Tue Sep 2 16:01:47 2008
>> @@ -0,0 +1,957 @@
>> +/*
>> + * Copyright (c) 2005, 2008 Sun Microsystems, Inc. All Rights Reserved.
>> + * Use is subject to license terms.
>> + *
>> + * Copyright (c) 1984 AT&T
>> + * All Rights Reserved
>> + *
>> + * Licensed under the Apache License, Version 2.0 (the "License");
>> + * you may not use this file except in compliance with the License.
>> + * You may obtain a copy of the License at
>> + * http://www.apache.org/licenses/LICENSE-2.0. + * + * Unless
>> required by applicable law or agreed to in writing, software + *
>> distributed under the License is distributed on an "AS IS" BASIS, + *
>> WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express + * or
>> implied. + * See the License for the specific language governing
>> permissions and
>> + * limitations under the License. + */
>> +
>> +#include "apr.h"
>> +#include "apr_lib.h"
>> +#include "libsed.h"
>> +#include "sed.h"
>> +#include "apr_strings.h"
>> +#include "regexp.h"
>> +
>> +char *trans[040] = {
>> + "\\01",
>> + "\\02",
>> + "\\03",
>> + "\\04",
>> + "\\05",
>> + "\\06",
>> + "\\07",
>> + "-<",
>> + "->",
>
> What are the above constants supposed to be. Opening the file in vi shows
> that they are special
> characters or better control characters. Looking with a hex editor these ()
> seem to be \\08.
> Is this correct?
Sed has a "l" command. From the sed man page :
(2)l List the pattern space on the standard out-
put in an unambiguous form. Non-printing
characters are spelled in two digit ASCII
and long lines are folded.
>From the code :
p3 = trans[(unsigned char)*p1-1];
while ((*p2++ = *p3++) != 0)
if(p2 >= eval->lcomend) {
*p2 = '\\';
wline(eval, eval->genbuf, strlen(eval->genbuf));
p2 = eval->genbuf;
}
It looks to me that it is trying to print character from value 0 to 31 as
printable characters.
>> + "-<",
>> + "->",
It seems to me that it should be \\08 and \\09.
I will dig deeper to see if these can be simplified. It looks little weird that
there are binary characters in source file.
Regards,
Basant.
