javeme commented on issue #1972:
URL:
https://github.com/apache/incubator-hugegraph/issues/1972#issuecomment-1279895505
我这边简单的构造了一个示例数据，尝试了一下如下语句是可行的：
```java
g.V().hasLabel('node').group().by{it.values('city',
'profession').toList()}.by(id)
```
示例数据：
```java
schema=graph.schema();
schema.propertyKey('profession').asText().ifNotExist().create();
schema.propertyKey('city').asText().ifNotExist().create();
schema.vertexLabel('node')properties('profession','city').useCustomizeNumberId().create();
schema.edgeLabel('child').sourceLabel('node').targetLabel('node').create();
g.addV('node').property(id, 1).property('profession',
"Java").property('city', 'Beijing').as('1')
.addV('node').property(id, 2).property('profession',
"Java").property('city', 'Beijing').as('2')
.addV('node').property(id, 3).property('profession',
"Java").property('city', 'Sanghai').as('3')
.addV('node').property(id, 4).property('profession', "DB").property('city',
'Sanghai').as('4')
.addE('child').from('1').to('2')
.addE('child').from('2').to('3')
.addE('child').from('4').to('3')
```
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