It is used in org.apache.jena.rdf.model.impl.Util namespace splitting code.
On Tue, Feb 13, 2018 at 4:44 PM, Andy Seaborne <a...@apache.org> wrote: > Where is XMLChar.isNameStart being used? > > > On 13/02/18 13:10, Claude Warren wrote: > >> Is there a reason that Jena does not support the full range of XML name >> start characters? >> >> see https://www.w3.org/TR/xml/#NT-NameStartChar >> >> I wrote a quick test and found that there were a number of characters that >> Jena does not support. >> Miscategorization appears to start at 0x132. There are 936990 >> miscategorized characters. >> >> The issue is actually in the Xerces util class XMLChar >> >> Is this because of the version of Xerces we are stuck with? Is there a >> way >> around this issue? >> >> Claude >> >> p.s. Since I can't attach a file, here is the test code I wrote. >> >> import static org.junit.Assert.assertTrue; >> >> import org.apache.xerces.util.XMLChar; >> import org.junit.Test; >> >> public class NameTest { >> /* >> * NameStartChar ::= ":" | [A-Z] | "_" | [a-z] | [#xC0-#xD6] | >> [#xD8-#xF6] | >> * [#xF8-#x2FF] | [#x370-#x37D] | [#x37F-#x1FFF] | [#x200C-#x200D] | >> * [#x2070-#x218F] | [#x2C00-#x2FEF] | [#x3001-#xD7FF] | >> [#xF900-#xFDCF] | >> * [#xFDF0-#xFFFD] | [#x10000-#xEFFFF] >> */ >> >> int[][] ranges = { { ':', ':' }, { 'A', 'Z' }, { '_', '_' }, { 0xC0, >> 0xD6 }, { 0xD8, 0xF6 }, { 0xF8, 0x2FF }, >> { 0x370, 0x37D }, { 0x37F, 0x1FFF }, { 0x200C, 0x200D }, { >> 0x2070, 0x218F }, { 0x2C00, 0x2FEF }, >> { 0x3001, 0xD7FF }, { 0xF900, 0xFDCF }, { 0xFDF0, 0xFFFD }, { >> 0x10000, 0xEFFFF } }; >> >> @Test >> public void testNameStart() { >> >> for (int[] range : ranges) { >> for (int c = range[0]; c <= range[1]; c++) { >> assertTrue( String.format( "character %s >> 0x%s",c,Integer.toHexString( c )) , XMLChar.isNameStart( c ) ); >> } >> } >> >> } >> >> @Test >> public void listNameStartErr() { >> int cnt = 0; >> for (int[] range : ranges) { >> for (int c = range[0]; c <= range[1]; c++) { >> if (!XMLChar.isNameStart( c )) >> { >> System.out.print( String.format( "0x%s >> ",Integer.toHexString( c )) ); >> cnt++; >> if (cnt % 25 == 0) >> { >> System.out.println(); >> } >> >> } >> >> } >> } >> System.out.println(); >> System.out.println( cnt+" characters miscategorized" ); >> } >> >> } >> >> >> -- I like: Like Like - The likeliest place on the web <http://like-like.xenei.com> LinkedIn: http://www.linkedin.com/in/claudewarren
