El lun, 26-01-2009 a las 00:45 -0800, Frank Hamilton escribió:
> Hi,
>
Hi Frank,
to start with if you are looking into pagination out of performance
consideration, then you may look into cocoon pagination.
See my recent post "How to use pipeline instead of jx for the view
layer" for more information about that.
> i have a jx file for presentation layer. In this file I write a table with
> the elements of a List that I get in de jx with
> usecase.getParameter(listUser).
> .
> .
>
> <jx:forEach var="lstEve" items="${usecase.getParameter('listUser')}">
> <tr class="forms-row-${repeaterLoop.index % 2}">
> <td><jx:out value="${lstEve.getNombre()}"/></td>
> <td>
> <p>
> <jx:out
> value="${lstEve.getDiaInicio()}"/>
> </p>
> <p>
> <jx:out
> value="${lstEve.getMesInicio()}"/>
> </p>
> <p>
> <jx:out
> value="${lstEve.getAnioInicio()}"/>
> </p>
> </td>
> </tr>
> .
> .
> I need to paginate that. Any ideas, Thanks!
IMO the best is to limit this in the usecase java class, meaning you
just send the list you want to show and the "page" you are right now.
...
int page = usecase.getParameter(listUserPage).
List listUser = getUsers(page);
usecase.addParamerter(LIST_USER,listUser);
usecase.addParamerter(LIST_CURRENT_PAGE,listUserPage);
...
private List getUsers(int page){
// connect to your ac provider and get all user
List allUser = acProvider.getAll();
List filteredUser = // filter list to only return the next page and then
return filteredUser;
}
HTH
salu2
--
Thorsten Scherler <thorsten.at.apache.org>
Open Source Java <consulting, training and solutions>
Sociedad Andaluza para el Desarrollo de la Sociedad
de la Información, S.A.U. (SADESI)
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