>- see footer for list info -<
Thanks Tim,

The trees are quite static and would rarely change once setup. They are only 
probably 4 or 5 levels in depth with relatively few branches at the top in 
order to arrive at the bottom level.

Thanks for your help.

Lee

---------- Original Message ----------------------------------
From: "Tim Blair" <[EMAIL PROTECTED]>
Reply-To: Coldfusion Development <[email protected]>
Date:  Mon, 10 Jan 2005 14:35:12 -0000

>>- see footer for list info -<
>Lee,
>
>> Loop over it and build an explorer tree ( using list items is
>> probably the easiest method).  Check if each item has child
>> items, if so add a nested list item.
>
>Depending on the potential size of the tree (length and depth) this may
>not be the best way to go about it.  For every node you have to check if
>there are any child nodes; this means that for a tree with 1000 nodes
>you have to do 1000 queries.  Not a good thing.  Sure, caching can
>alleviate the vast majority of this, but if the tree is changing
>frequently then the cache can be irrelevant.
>
>This topic of conversation comes up again and again; you'll find
>discussions to almost religious levels if you do a quick search.  One of
>the more often cited methods of handling large trees in SQL is the
>"nested sets model".
>
>Using nested sets is a lot more complicated than the standard "adjacency
>list" method (i.e. child-parent pairs) you've used (especially if you're
>like me and are using an old version of MySQL without sub-selects!) but
>it provides so much more flexibility.  Using a nested set model, I can
>pull out my entire tree, including parent/child relationships and node
>depths, with just a single query.
>
>Here's some links to more info about trees in SQL, including discussion
>on why the adjacency list model is bad and nested sets are good :) (at
>least for large trees):
>
>http://c2.com/cgi/wiki?TreeInSql
>http://www.dbmsmag.com/9603d06.html
>http://short.badpen.com/?RR0F83YD
>
>Of course, if the tree is small and the extra queries won't really
>affect anything, then Russ' solution fits the bit perfectly.
>
>Tim.
>
>
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