>- see footer for list info -<
Thanks for that, Peter.
I tested it and it worked ok on the second url but left &oq= (empty
variable value) on the first one. Regex seems extremely powerful but
difficult to get exactly what you need.
So, I though it maybe easier to alter the way I search for q= in the url,
rather than
remove what i didn't want.
<cfset startpos = ReFindNoCase("[\?|&]q=.",myref)>
<cfset endpos = mid(myref,startpos+3,Len(myref))> (3 is &q= or ?q=)
<cfset keywords = ReReplaceNoCase(endpos,'&.*','','all')>
<cfset keywords = URLDecode(Keywords)>
Time to get a decent Regex book i reckon.
--- On Mon, 20/7/09, Peter Boughton <[email protected]> wrote:
From: Peter Boughton <[email protected]>
Subject: Re: [CF-Dev] Regular Expression Help
To: "Coldfusion Development" <[email protected]>
Date: Monday, 20 July, 2009, 12:10 PM
>- see footer for list info -<
Try this:
<cfset myref = myref.replaceAll( '(?<=[&?])[a-z]+q=[^&]++&?' , '' ) />
That's using Java regex (the string.replaceAll func) since regular
CFML regex doesn't support lookbehinds - will work in all regex
engines that run on Java.
And to explain that regex, here's it disected in comment mode:
(?x) # enable regex comment mode
(?<=[&?]) # start with either & or ? but don't include in match
[a-z]+q= # one or more a-z followed by q=
[^&]++ # possessively match any non-ampersand
&? # optionally match ampersand to avoid result having ?& or
&& after replace.
All make sense?
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