Github user nickwallen commented on the issue: https://github.com/apache/metron/pull/681 Based on the link that you embedded in the tests, your implementation seems correct. I assume that these grammar rules are well reasoned and necessary, but it surely seems counter-intuitive to me for this use case. > The equality operator == returns false if either operand is NaN. > The inequality operator != returns true if either operand is NaN (§15.21.1). > In particular, x!=x is true if and only if x is NaN, and (x<y) == !(x>=y) will be false if x or y is NaN. Am I thinking about this all wrong? Maybe I just need some lunch to get my blood sugar up. :)
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