Github user nickwallen commented on the issue:
https://github.com/apache/metron/pull/681
Based on the link that you embedded in the tests, your implementation seems
correct. I assume that these grammar rules are well reasoned and necessary,
but it surely seems counter-intuitive to me for this use case.
> The equality operator == returns false if either operand is NaN.
> The inequality operator != returns true if either operand is NaN
(§15.21.1).
> In particular, x!=x is true if and only if x is NaN, and (x<y) == !(x>=y)
will be false if x or y is NaN.
Am I thinking about this all wrong? Maybe I just need some lunch to get
my blood sugar up. :)
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