Hi Ricard,
no, this is not a bug. findComponent is supposed to work from the
enclosing naming container. If you need to search without this, you
need to traverse the hierarchy. I do think I remember we implemented
"::text" for a case like this already in the standard - in any case,
the component libraries I am using imlement this already ;)
best regards,
Martin
On Tue, Jun 21, 2011 at 3:06 PM, RICARD MORE FARRES
<ricard.m...@mango.com> wrote:
> Thanks Leonardo,
>
> Already done, but I have another question:
>
> Which is the reason that UIComponentBase.findComponent(String expr) looks for
> the searched component, starting from the closest parent that implements
> NamingContainer?
> Look at this example:
>
> <h:outputText id="text" value="#{bean.texto}"></h:outputText>
> <ui:repeat id="repeat" value="#{bean.textos}" var="texto">
> <h:commandLink id="command" value="#{texto}">
> <f:ajax event="click" listener="#{bean.actionListener}" render="text"/>
> </h:commandLink>
> </ui:repeat>
>
> If we try to render this view, we get:
> javax.faces.FacesException: Component with id:texto not found
>
> This exception is trown by HtmlAjaxBehaviorRenderer.mapToString when he find
> every component identified in the render attribute. I think they converts the
> id's in the render attribute, to the clientId of every component referenced.
> The problem is that UIRepeat implements NamingContainer, so the commandLink
> inside that UIRepeat is gonna search the component identified by 'text'
> inside the children list of repeat tag.
> But it should works, isn't it? Nothing wrong to re render an outputtext from
> command link that is inside a repeat.
> I have reimplemented method findComponent in my own components, in order to
> find the id starting from the view root... and it works.
>
> Is this another bug?
>
> Regards,
> Ricard
>
> -----Mensaje original-----
> De: Leonardo Uribe [mailto:lu4...@gmail.com]
> Enviado el: lunes, 20 de junio de 2011 19:09
> Para: MyFaces Development
> CC: RICARD MORE FARRES
> Asunto: Re: UIRepeat offset and size problem
>
> Hi
>
> It is a bug. Please create an issue here:
>
> https://issues.apache.org/jira/browse/MYFACES
>
> I have already a patch, so as soon as you create the issue I'll commit
> it. Later, you can get a nightly build snapshot here:
>
> https://repository.apache.org/content/repositories/snapshots/org/apache/myfaces/core/
>
> regards,
>
> Leonardo Uribe
>
> 2011/6/20 RICARD MORE FARRES <ricard.m...@mango.com>:
>> Hello,
>>
>>
>>
>> I am testing MyFaces 2.1.1 implemantation, in order to upgrade our
>> aplication from version 1.2.7.
>>
>>
>>
>> I have found a problem with parameters offset and size of ui:repeat tag.
>>
>> offset sets the first index of the list to iterate over.
>>
>> size is the number of element to iterate.
>>
>>
>>
>> If I have a list of Strings like this:
>>
>> private String[] textos = new String[] {"B1", "B2", "B3", "B4", "B5", "B6",
>> "B7"};
>>
>>
>>
>> public String[] getTextos() {
>>
>> return textos;
>>
>> }
>>
>>
>>
>> And I declare repeat tag:
>>
>> <ui:repeat value="#{bean.textos}" var="texto" offset="0" size="1">
>>
>> <h:outputText value="#{texto}"/><br/>
>>
>> </ui:repeat>
>>
>>
>>
>> It shows elements B1 and B2 (iterate over indexes 0 and 1). If I change
>> offset to 1, it will show elements B2 and B3.
>>
>> But if I set offset="2" in order to ietare over indexes 2 and 3 (elements B3
>> and B4), I get an exception:
>>
>>
>>
>> javax.faces.FacesException: iteration offset cannot be greater than
>> collection size
>>
>> at
>> org.apache.myfaces.view.facelets.component.UIRepeat._validateAttributes(UIRepeat.java:552)
>>
>> at
>> org.apache.myfaces.view.facelets.component.UIRepeat.process(UIRepeat.java:581)
>>
>> ...
>>
>>
>>
>> If I want to avoid this error, size must be allways greater tha offset, but
>> it should be possible to iterate over last two elements of a 102 elements
>> list starting from index 100, for example (offset=100,size=1).
>>
>> And should not be "1" the lower value for size? Now, if you set 0 to size,
>> ui:repeat iterates once...
>>
>>
>>
>> Thanks in advance,
>>
>> Ricard
>>
>>
>>
>>
>>
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