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https://issues.apache.org/jira/browse/NUTCH-1630?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=13875902#comment-13875902
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Tejas Patil commented on NUTCH-1630:
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Hi [~icebergx5],
How do you obtain the average response time of previous depth ? I was hoping
that it would be somewhere in the fetch phase where you somehow stored the
response timings for each host then then pass on that information to the
generate phase.
> How to achieve finishing fetch approximately at the same time for each queue
> (a.k.a adaptive queue size)
> ---------------------------------------------------------------------------------------------------------
>
> Key: NUTCH-1630
> URL: https://issues.apache.org/jira/browse/NUTCH-1630
> Project: Nutch
> Issue Type: Improvement
> Affects Versions: 2.1, 2.2, 2.2.1
> Reporter: Talat UYARER
> Labels: improvement
> Fix For: 2.3
>
> Attachments: NUTCH-1630.patch, NUTCH-1630v2.patch
>
>
> Problem Definition:
> When crawling, due to unproportional size of queues; fetching needs to wait
> for a long time for long lasting queues when shorter ones are finished. That
> means you may have to wait for a couple of days for some of queues.
> Normally we define max queue size with generate.max.count but that's a static
> value. However number of URLs to be fetched increases with each depth.
> Defining same length for all queues does not mean all queues will finish
> around the same time. This problem has been addressed by some other users
> before [1]. So we came up with a different approach to this issue.
> Solution:
> Nutch has three mods for creating fetch queues (byHost, byDomain, ByIp). Our
> solution can be applicable to all three mods.
> 1-Define a "fetch workload of current queue" (FW) value for each queue based
> on the previous fetches of that queue.
> We calculate this by:
> FW=average response time of previous depth * number of urls in current
> queue
> 2- Calculate the harmonic mean [2] of all FW's to get the average workload of
> current depth (AW)
> 3- Get the length for a queue by dividing AW by previously known average
> response time of that queue:
> Queue Length=AW / average response time
> Using this algoritm leads to a fetch phase where all queues finish up around
> the same time.
> As soon as posible i will send my patch. Do you have any comments ?
> [1] http://osdir.com/ml/dev.nutch.apache.org/2011-11/msg00101.html
> [2] In our opinion; harmonic mean is best in our case because our data has a
> few points that are much higher than the rest.
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