Delete Query transformed into a Select Query
--------------------------------------------

                 Key: OPENJPA-270
                 URL: https://issues.apache.org/jira/browse/OPENJPA-270
             Project: OpenJPA
          Issue Type: Bug
          Components: jpa, query
    Affects Versions: 0.9.7
         Environment: Java JRE 1.5
OpenJPA 0.9.7
IDE Eclipse
MySQL 4.1.9 DataBase (EasyPhp 1.8.0.1)
            Reporter: Frederic Jeanneau


Hello.
I'm french, so excuse my english.

I have a problem while trying to delete (and so update) an object.
The JQL syntax is correct (i think), but at the executeUpdate(), the query is 
transformed into a select.

First, my object :

I have classical - test objects : employees, persons, service.
An employee is a person affected to a service
A service as a number and a name
A person has a number ID, a name and a surname.


First, the Person :

@Embeddable
@Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)
@Table(name = "PERS")
public class PersonneR implements comparable {
        @Id
        @Column(name = "SSID", nullable = false, length = 40)
        private int SSid;
        @Basic
        @Column(name = "PERS_NOM", nullable = false, length = 40)
        private String nom;
        @Basic
        @Column(name = "PERS_PRENOM", nullable = false, length = 40)
...
}

Then my Employee class :

@Entity
@Inheritance (strategy = InheritanceType.TABLE_PER_CLASS)
@Table(name = "EMPL")
public class EmployeR implements Comparable {
        @EmbeddedId
        private PersonneR pers;
        @ManyToOne (optional = false,cascade = {CascadeType.PERSIST }) 
@JoinColumn(name = "NUM", unique = false, nullable = false, updatable = false, 
referencedColumnName = "NUM", table = "SERV")
        private ServiceR affectation;

...
}

The Service class is not important but i put it here :

@Entity
@Inheritance (strategy = InheritanceType.TABLE_PER_CLASS)
@Table(name = "SERV")
public class ServiceR implements Comparable {
        @Id
        @Column(name = "NUM", nullable = false, length = 5)
        private int numero;
        @Basic
        @Column(name = "SERV_NOM", nullable = false, length = 40)
        private String nom;
...
}

So, then I create an Entity manager, persist an employee and service.
I have 2 tables :
Table "empl" for the person/employee (SSID,PERS_NOM,PERS_PRENOM,affectation_NUM)
Primary key (SSID,PERS_NOM,PERS_PRENOM) (fields of the type Person)

Table "serv" for the service (NUM, SERV_NOM)
Primary Key : Num


But when I try to delete an employee (num 1, name "prenom1", surname "nom1") 
who had been persisted,
whith the following query :

// PersonneR pers is the pers fiel of the EmployeR object I want to delete.
Query qp = this.em.createQuery("DELETE FROM EmployeR t0 where (t0.pers=?1)");
qp.setParameter(1, pers);
int deleted = qp.executeUpdate();

I have the following trace :

2165  empjpa  TRACE  [main] openjpa.jdbc.SQL - <t 32519825, conn 6237616> 
executing prepstmnt 3157607 SELECT t0.SSID, t0.PERS_NOM, t0.PERS_PRENOM, 
t1.NUM, t1.SERV_NOM FROM EMPL t0 INNER JOIN SERV t1 ON t0.affectation_NUM = 
t1.NUM WHERE (t0.SSID = ? AND t0.PERS_NOM = ? AND t0.PERS_PRENOM = ?) 
[params=(int) 1, (String) nom1, (String) prenom1]
2165  empjpa  TRACE  [main] openjpa.jdbc.SQL - <t 32519825, conn 6237616> [0 
ms] spent
0 lignes effacées.

And there is a "select" where I wanted a "delete".
The JPQL query is, in my opinion, correct, and the where clause is correctly 
understood by OpenJPA.

I also tried to do as in some examples "delete t0 from EmployeR to where ...." 
but OpenJPA don't want "to" before "from"...
I also tried a native query, but OpenJPA don't want to call a native sql query 
because "it is not supported"...

So, if someone know how to delete by query, or why OpenJPA launch a select 
query, I'm waiting for their ideas, and i'm still trying to solve the problem.

thanks for your help

-- 
This message is automatically generated by JIRA.
-
You can reply to this email to add a comment to the issue online.

Reply via email to