Hi Rainman,
> After a period of time of developing with URE, I find the C++ UNO
> class Reference is not very comfortable for use sometime.
> The problem is, when I have a reference of base interface XA and a
> reference of derived interface XB, I can't make xA = xB directly.
> Instead I have to query XA from xB like this xA = Reference<XA>::query(xB).
¨xA = xB.get()¨ would do, too, and be less expensive.
> I wonder that whether we can use template constructors to simply this
> situation.These constructors may something like this:
>
> template <typename interface_type>
> class Reference
> {
> template <_interface_type>
> Reference(const Reference<_interface_type>& rRef)
> {
> interface_type* p = NULL;
> _interface_type* _p = NULL;
> p = _p; // compiling time cast check.
> _pInterface = iquery( rRef.get() );
The last two lines could be to just assigning (and aquiring) rRef.get()
to _pInterface.
> }
> ...
> Now we can simplify the cast code above to
> xA = xB;
I am not sure we should do this, implicit constructors usually add
ambiguity ...
Ciao
Frank
--
- Frank Schönheit, Software Engineer [email protected] -
- Sun Microsystems http://www.sun.com/staroffice -
- OpenOffice.org Base http://dba.openoffice.org -
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