Not as such. But I think RelOptUtil.conjunctions(RexNode) and
.disjunctions(RexNode) will make the task easier.
Given an expression in DNF, rex = ā(a AND b) OR cā, the following loop will
decompose into parts:
for (RexNode disjunction : disjunctions(rex)) {
for (RexNode conjunction : conjunctions(disjunction)) {
...
}
}
Julian
PS For those not into the jargon:
http://en.wikipedia.org/wiki/Disjunctive_normal_form
On Aug 29, 2014, at 12:18 PM, John Pullokkaran <[email protected]>
wrote:
> Is there a utility in Optiq that can convert DNF to CNF?
>
> Thanks
> John
>
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