What is 'p' in this example? On Wednesday, October 17, 2012, Sam Tobin-Hochstadt wrote:
> On Tue, Oct 16, 2012 at 7:55 PM, Stephen Bloch > <bl...@adelphi.edu<javascript:;>> > wrote: > >>> Another data point: If "define/match" expands to a "define" of a > procedure > >>> that dispatches to a set of implementations based on a pattern-match of > >>> actual arguments... then the name is exactly what I'd expect for such a > >>> feature in a Scheme dialect. > >> > >> That is, in fact, exactly what it does. > > > > Cool! My students have been writing code that way for years, and I've > been telling them "There are languages in which that would work, but Scheme > isn't one of them." > > > > (define (swap (make-posn x y)) > > (make-posn y x)) > > The syntax looks like: > > (define/match (swap p) > [(posn x y) (posn y x)]) > > -- > sam th > sa...@ccs.neu.edu <javascript:;> > _________________________ > Racket Developers list: > http://lists.racket-lang.org/dev >
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