Oh, now I get what you meant in your original message. Right. Robby
On Mon, Dec 9, 2013 at 3:29 PM, Sam Tobin-Hochstadt <sa...@cs.indiana.edu>wrote: > I haven't found a way to make it happen yet. But even so, it seems > like the wrong name. > > Sam > > On Mon, Dec 9, 2013 at 4:16 PM, Robby Findler > <ro...@eecs.northwestern.edu> wrote: > > Is it possible that that name can leak out in an error message? > > > > Robby > > > > > > > > On Mon, Dec 9, 2013 at 3:10 PM, Sam Tobin-Hochstadt < > sa...@cs.indiana.edu> > > wrote: > >> > >> Currently, this program fails with a somewhat bizarre type error: > >> > >> #lang typed/racket > >> > >> (: foo ([#:k Any] -> Integer)) > >> (define (foo #:k [s #f]) 0) > >> > >> (let: ([i : Integer (foo #:k #t)]) i) > >> > >> The reason is that the expansion of keyword applications generates a > >> name to use for the function (here `foo`), and it uses > >> `syntax-local-infer-name` to get the name to use. Unfortunately, in > >> this case, it produces `i`, an identifier which has an extra syntax > >> property saying that `i` is an `Integer`. Of course, `foo` isn't an > >> integer, it's a function, and so we get a type error. > >> > >> I don't see why the inferred name is the right choice here -- there's > >> no connection between `i` and the name of the function. I can just > >> change this to use a fresh name, but I thought I'd ask first. > >> > >> Sam > >> _________________________ > >> Racket Developers list: > >> http://lists.racket-lang.org/dev > > > > >
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