http://issues.apache.org/SpamAssassin/show_bug.cgi?id=4859
------- Additional Comments From [EMAIL PROTECTED] 2006-04-08 16:59 -------
(In reply to comment #3)
> Both work, but the first sets the scalar to a blank array reference, and the
second sets the scalar to a blank
> hash reference. :)
It occurred to me that I was wrong about this. "$var = ()" seems to set $var to
undef (I would have thought it would set it to "0", but testing it shows undef).
"$var = []" sets it to an array reference, of course. and "$var = {}" as
previously mentioned, sets $var to a hash reference.
just wanted to correct myself. :)
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