I believe I logged an issue first and I should get a response first.
I was ignored.
Regards
Did you know there are 8 million people in kashmir locked up in their homes
by the Hindutwa (Indians)
for 8 months.
Now the whole planet is locked up in their homes.
You didn't take notice of them either.
you ignored them.
Backbutton.co.uk
¯\_(ツ)_/¯
♡۶Java♡۶RMI ♡۶
Make Use Method {MUM}
makeuse.org
<http://www.backbutton.co.uk>
On Thu, 26 Mar 2020 at 17:24, Enrico Minack <m...@enrico.minack.dev> wrote:
> Abhinav,
>
> you can repartition by your key, then sortWithinPartition, and the
> groupByKey. Since data are already hash-partitioned by key, Spark should
> not shuffle the data hence change the sort wihtin each partition:
>
> ds.repartition($"key").sortWithinPartitions($"code").groupBy($"key")
>
> Enrico
>
> Am 26.03.20 um 17:53 schrieb Ranjan, Abhinav:
>
> Hi,
>
> I have a dataframe which has data like:
>
> key | code | code_value
> 1 | c1 | 11
> 1 | c2 | 12
> 1 | c2 | 9
> 1 | c3 | 12
> 1 | c2 | 13
> 1 | c2 | 14
> 1 | c4 | 12
> 1 | c2 | 15
> 1 | c1 | 12
>
>
> I need to group the data based on key and then apply some custom logic on
> every of the value I got by grouping. So I did this:
>
> lets suppose it is in a dataframe df.
>
> *case class key_class(key: string, code: string, code_value: string)*
>
>
> df
> .as[key_class]
> .groupByKey(_.key)
> .mapGroups {
> (x, groupedValues) =>
> val status = groupedValues.map(row => {
> // do some custom logic on row
> ("SUCCESS")
> }).toList
>
> }.toDF("status")
>
>
> The issue with above approach is the values I get after applying
> groupByKey are not sorted/ordered. I want the values to be sorted by the
> column 'code'.
>
> There is a way to do this:
>
> 1. get them in a list and then apply sort ==> this will result in OOM if
> the iterartor is too big.
>
> 2. I think some how to apply the secondary sort, but problem with that
> approach is I have to keep track of the key change.
>
> 3. sortWithinPartitions cannot be applied because groupBy will mess up the
> order.
>
> 4. Another approach is:
>
> df
> .as[key_class]
> .sort("key").sort("code")
> .map {
> // do stuff here
> }
>
> but here also I have to keep track of the key change within map function,
> and sometimes this also overflows if the keys are skewed.
>
>
>
> *So is there any way in which I can get the values sorted after grouping
> them by a key.??*
>
>
> *Thanks,*
>
>
> *Abhinav *
>
>
>
