Kathleen Ting created SQOOP-489:
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Summary: Cannot define partition keys for Hive tables create
through sqoop
Key: SQOOP-489
URL: https://issues.apache.org/jira/browse/SQOOP-489
Project: Sqoop
Issue Type: Bug
Affects Versions: 1.4.1-incubating
Reporter: Kathleen Ting
By enabling the "--table" option, Sqoop includes every column in the table in
the create table query, and by enabling the "--hive-partition-key" option,
Sqoop blindly appends the "partitioned by" clause. Now if you specify one of
columns in the table in the "--hive-partition-key", this will cause a syntax
error in Hive.
For example, if we have a table 'FOO' that has columns 'I' and 'J':
sqoop create-hive-table --table FOO ...
will generate the following Hive query:
CREATE TABLE IF NOT EXISTS `FOO` ( `I` STRING, `J` STRING)
Now if we add "--hive-partition-key I" to the command, Sqoop generates the
following query:
CREATE TABLE IF NOT EXISTS `FOO` ( `I` STRING, `J` STRING) PARTITIONED BY (I
STRING)
The problem is that since 'I' is defined twice (once in CRATE TABLE and once in
PARTITIONED BY), this is a syntax error in Hive.
This correct query would be something like:
CREATE TABLE IF NOT EXISTS `FOO` (`J` STRING) PARTITIONED BY (I STRING)
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