Hi all,
Currently, the usage of UDFs is restricted to simply being able to call the UDF
and assign the results to a variable. If the user wishes to use the UDF as
input to a built-in op of any sort on the same line, an error is thrown. This
is confusing for users, and leads to messy code involving temporary variables.
Here is a simple example that does not work, yet should:
out = my_udf_func(x) + 4
Can we please fix this? UDFs should be treated like any other op.
Thanks,
- Mike
--
Mike Dusenberry
GitHub: github.com/dusenberrymw
LinkedIn: linkedin.com/in/mikedusenberry
Sent from my iPhone.
